What is an equation of the line that passes through the points (6,4) and (4,1)

First, you find the slope.

This is done by plugging in to the equation y2 - y1 / x2 - x1

Let 6 and 4 by x2 and y2 and 4 and 1 be x1 and y1.

4-1 / 6-4 = 3/2

The slope is 3/2.

Now, y = 3/2 x +b

To solve for b, plug in a point.

I plugged in (6, 4)

4 = 3/2(6) + b

4 = 9 + b

-5 = b

So, the equation is y = 3/2 x - 5

Hope this helps