Given h(x)=-x-1,find h(-2)

Given that : h(x) = - x - 1 .

And we are required to find the value of h(-2) .

For this just in place of x replace it by -2 .

So ,

=> h(x) = - x - 1.

=> h(x) = - ( x + 1 ) .

=> h(-2) = - ( -2 + 1 )

=> h(-2) = - 1 × -1 .

=> h(-2) = 1

Hence the required answer is 1

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

i pretty sure it is