Karen walks 6 miles in 2 hours. what is her unit rate?

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

Segment wx is shown explain how you would construct a perpendicular bisector of wx using a compass and a straightedge

5. write an equation for the line that is parallel to the given line and that passes through the given point. y = –5x + 3; (–6, 3)