Simon went to high school from 2012 to 2017. He was born when his father was 25. Simon’s parents met while they were in high school together. Part A Choose the compound inequality that describes the year x when Simon’s parents met.

Simon started High school in the year 2012.

One usually starts highs school when is 14 years old.

So we can assume that Simon was born 14 years before 2012:

2012 - 14 = 1998

Now, Simon's parents may have met in the beginning of 1998, and Simon was born by the end of 1998. But in that case, Simon would be 13 at the beginning of school, instead of 14.

Then Simon's parents should have met before 1998.

Then the inequality that we have:

x < 1998.

And Simon was born when his father was 25 years old.

Then in 1998, Simon's father was 25 years old.

Meaning that he was born around:

1998 - 25 = 1973.

This means that Simon's parents met in-between the years 1973 and 1998.

1973 < x < 1998

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated