If f(x)=3x^2 +2 and g(x)= x^2 + 2x, what is f(g(x)) when x=2?

Step-by-step explanation:

f(g(x))=3(x^2+2x)^2+2=3(x^4+2*x^2*2x+4*x^2)+2

=3x^4+3*4*x^3+12*x^2+2=

=3x^4+12x^3+12x^2+2 for x=2

=3*2^4+12*2^3+12*2^2+2=

=3*16+12*8+12*4+2

=48+96+48+2=

=144+50=194

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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