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In rhombus ABCD , m∠BCE=33∘ .

What is m∠ABE ?

57 deg

Step-by-step explanation:

Rhombus ABCD has diagonals AC and BD which intersect at point E.

The diagonals of a rhombus divide the rhombus into 4 congruent triangles.

If you find the measures of the angles of one of the triangles, then you know the measures of the angles of all 4 triangles.

Also, the diagonals of a rhombus are perpendicular.

Look at triangle BCE.

m<BCE = 33

m<BEC = 90

m<BCE + m<BEC + m<CBE = 180

33 + 90 + m<CBE = 180

m<CBE = 57

<ABE in triangle ABE corresponds to <CBE in triangle BCE.

m<ABE = m<CBE = 57

57 deg

me

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it