Our friend claims that a rectangle with the same perimeter as △QRS will also have the same area. Is your friend correct? Explain. yes; Any rectangle with a perimeter of 12 units will have an area of 6 units. yes; If a rectangle does not have the same perimeter as △QRS, it will not have the same area, so your friend's statement is correct by counterexample. no; A rectangle cannot have a perimeter of 12 units and an area of 6 square units. no; A 1×5 rectangle has a perimeter of 12 units and does not have an area of 6 units, so a counterexample shows that your friend's statement is not correct.

A rectangle cannot have a perimeter of 12 units and an area of 6 square units. no

Step-by-step explanation:

We are given vertices in the attached

To solve this question, we are given vertices, we solve using the formula:

√(x2 - x1)² +(y2 - y1)² when given (x1, y1) and (x2, y2)

We are given Triangle QRS

Where: Q = (-2, 1) , R = (-2, -2), S =(2, -2)

QR : Q = (-2, 1) , R = (-2, -2)

= √(-2 - (-2))² + (-2 - 1)²

= √0² + 3²

= √9

= 3 units

RS : R = (-2, -2), S =(2, -2)

= √(2 -(-2))² + (-2 - (- 2))²

= √4² + (0)2

= √16

= 4 units

QS: Q = (-2, 1), S =(2, -2)

= √(2 -(-2))² + (-2 - 1)²

= √(2 + 2)² + (-3)²

= √4² + 9

= √16 + 9

= √25

= 5 units

The Area of Triangle QRS = 1/2bh

b = base = RS = 4 units

h = height = QR = 3 units

= 1/2 × 4 × 3

= 6 square units

Perimeter of Triangle QRS = QR + RS + QS

=( 3 + 4 + 5)units

= 12 units

Our friend is claiming that a rectangle with the same perimeter as will have the same area as the triangle

The perimeter of a rectangle

= 2L + 2W

12 units = 2L + 2W

12 - 2L = 2W

W = 12 - 2L/2

The Area of a Rectangle = L × W

6 square units = LW

6 = LW

6 = L ×(12 - 2L/2)

6 = 12L - 2L²/2

Cross Multiply

6 × 2 = 12L - 2L²

12 = 12L - 2L²

2L² - 12L + 12

2(L² - 6L + 6)

Therefore, from the calculation above, we can conclude:

A rectangle cannot have a perimeter of 12 units and an area of 6 square units. no.

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two