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Mathematics, 16.10.2020 15:01 maybaby9625

Solve the system of equations. 3x + 3y + 62 = 3
3x + 2y + 62 = 7
4x + 4y + 72 = 4
a. (x = 5, y = - 4,2 = 0)
b. (x = 4, y = -3, 2 = 1)
c. (x = 6, y=-5,2=-1)
d. (x = 7, y=-6, z = 2)


Solve the system of equations.

3x + 3y + 62 = 3
3x + 2y + 62 = 7
4x + 4y + 72 = 4
a. (x = 5, y =

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Answers: 1

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Solve the system of equations. 3x + 3y + 62 = 3
3x + 2y + 62 = 7
4x + 4y + 72 = 4
...
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