Find the value(s) of "k" that will cause the equation 4x^2 +kx + 4 to have one real solution.

 k = {8, -8}

Step-by-step explanation:

In order for a quadratic equation to have exactly one solution, the discriminant must equal zero.       →        b² - 4ac = 0

  4x² + kx + 4 = 0

  ↓       ↓      ↓

a=4    b=k    c=4

b² - 4ac = 0

k² - 4(4)(4) = 0

k²             = 64

           k = √64

           k = ± 8

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1