The sum of two numbers is 72. One number is 8 more than the other. Find the numbers.
Can someone help me?

32 and 40

Step-by-step explanation:

Let's call the smaller number x. If the smaller number is x, the equation for this problem is 2x + 8 = 72

Equation:

2x + 8 = 72

2x = 64

x = 32

So now we know the smaller number is 32, so now add 8 and we get 40.

Therefore the 2 numbers are 32 and 40

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted