What is the value of 4(x-2)(x-3)+7(x-2)(x-5)-6(x-3)(x-5) when x=5

The required value of equation at x = 5 is 24.

Given ;

Equation is = 4(x-2)(x-3) + 7(x-2)(x-5) - 6(x-3)  

We have to calculate the value of expression when x = 5

To solve the equation substitute x = 5 in the given equation

= 4(x-2)(x-3) + 7(x-2)(x-5) - 6(x-3)(x-5)

= 4(5-2)(5-3) + 7(5-2)(5-5) - 6(5-3)(5-5)

Simplify the equation

= 4(3)(2) + 7(3)(0) - 6(2)(0)

= 4.(6) + 7(0) - 6(0)

= 24 + 0 - 0

= 24

The required value of the equation at x = 5 is 24.

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The value is 24

Step-by-step explanation:

We want to find the value of the given expression when x = 5

Simply substitute 5 into the given expression.

Thus, we have;

4(5-2)(5-3) + 7(5-2)(5-5) - 6(5-3)(5-5)

Any part of the expression with 5-5 will be zero and will cancel out

Thus, we have

4(3)(2) = 4 * 3 * 2 = 24

$9.41

step-by-step explanation:

the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. hope this ! mark brainliest! you v much! : )