Pool #1 is a rectangle that is 14 feet wide. The length is (14– 8)2ft. The dimensions of the pool are: Length= ft Width=ft

the length is 6 feet. The width is 2 feet

Step-by-step explanation:

The garden pool is rectangular in shape.

Let L represent the length of the rectangular garden.

Let W represent the width of the rectangular garden.

The area of a rectangle is expressed as L× W. The area of the rectangular garden pond is 12ft^2. It means that

L× W = 12 - - - - - - - - - - 1

The length of the pool needs to be 2ft more than twice that width. This means that

L = 2W + 2 - - - - - - - - - - - 2

Substituting equation 2 into equation 1, it becomes

W(2W + 2) = 12

2W^2 + 2W = 12

2W^2 + 2W - 12 = 0

W^2 + W - 6 = 0

W^2 + 3W - 2W - 6 = 0

W(W + 3) - 2(W + 3) = 0

W - 2 = 0 or W + 3 = 0

W = 2 or W = - 3

Since the Width cannot be negative, then the width is 2 feet

Substituting W = 2 into equation 2. It becomes

L = 2×2 + 2 = 6 feet

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept

250

step-by-step explanation: