Find the center and the radius of the circle with the equation: x^2 - 2x + y^2 + 4y + 1 = 0.

A). center: (1,2)
radius: 4

B). center (2, -4)
radius: 1

C). center: (1, 2)
radius: 2

D). center: (1, -2)
radius: 2

D

Step-by-step explanation:

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb