One model for car depreciation is as follows, where Cis the original cost, Vis the value of the car after tyears, and ris the rate of depreciation
V= (1-1)
If the original cost of the car was $21,000 and the rate of depreciation is 15%, what will be the value of the car after 5 years?
[Round to the nearest dollar.]
A. $17,850
B. $3,150
C. $9,318
D. $19,472

Given:

Original cost of car = $21000

Rate of depreciation = 15% = 0.15

Time = 5 years

To find:

The value of car after 5 years.

Solution:

Consider the model for car depreciation is

where,  C is the original cost, V is the value of the car after t years, and r is the rate  of depreciation.

Substitute C=21000, r=0.15 and t=5 in the above model.

The value of car after 5 years is $9318. Therefore, the correct option is C.

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4