Function A(e) represents the surface area of a cube in terms of its edge length, e, and the difference quotient is 12e + 6h. What is the average rate of change in surface area of a cube as the edge length increases from 3 inches to 5 inches? 48 square inches per inch
54 square inches per inch
66 square inches per inch
96 square inches per inch

48 square inches per inch

Step-by-step explanation:

The surface area of a cube of sidelength e is:

A(e) = 6*e^2.

The rate of change is:

A'(e) = 2*6*e

The average rate of change between 3 in and 5 in is:

r  = (A(5in) + A(3in))/2 = (2*6*5in + 2*6*3in)/2 = 48in

Now, the options are given in:

"squere inches per inch"

This is written as:

in^2/in = in.

Then we can write our above rate as:

r = 48in = 48in^2/in = 48 square inches per inch.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?