A ball is dropped from a height of 100 cm. The rebound heights to the nearest centimeter are 60, 36, 22, What is the total distance the ball will travel both up an down?

400 cm

Step-by-step explanation:

Given that:

Initial height at which ball was dropped = 100m

Rebound heights to the nearest cm = 60, 36, 22...

First we find the rebound percentage x;

x% * 100m = 60

100x % = 60

x = 60%

Hemce, we need to calculate the rebound velocities which aren't given:

0.6 * 22 = 13.2 = 13cm

0.6 * 13 = 7.8 = 8cm

0.6 * 8 = 4.8 = 5cm

0.6 * 5 = 3cm

0. 6 * 3 = 1.8 = 2 cm

0.6 * 2 = 1.2 = 1cm

The total distance the ball travels UP and DOWN :

(100 + 2(60) + 2(36) + 2(22) + 2(13) + 2(8) + 2(5) + 2(3) + 2(2) + 2(1))

= 400 cm

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step-by-step explanation:

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step-by-step explanation:

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