A sequence can be generated by using an=an−1+9, where a1=−5 and n is a whole number greater than 1. What are the first four terms in the sequence? A.−5, 4, 13, 22
B.9, 4, −1, −6
C.−5, −45, −405, −3645
D. 9, −45, 225, −1125

B.9, 4, −1, −6

Step-by-step explanation:

A sequence can be generated by using an=an−1+9, where a1=−5 and n is a whole number greater than 1. What are the first four terms in the sequence?

A.−5, 4, 13, 22

B.9, 4, −1, −6

C.−5, −45, −405, −3645

D. 9, −45, 225, −1125

From the above question,

A sequence can be generated by using an=a(n−1)+9, where a1=−5

The formula = an = a1 + (n - 1)d

a1 = First term

d = common difference = 9

We are to find the first 5 terms

First term = a1 =

an=an−1+9, where a1=−5

The formula =

a1 = -5 (1 - 1) + 9

= -5(0) 9

= -9

Second term = a2 =

an=an−1+9, where a1=−5

The formula = an = a1 (n - 1) + d

a2 = -5(2 - 1) + 9

= -5(1)+ 9

= -5 + 9

= 4

Third term = a3 =

an=an−1+9, where a1=−5

The formula = an = a1(n - 1) + d

a3 = -5(3 - 1)9

= -5(2) + 9

= -10+ 9

= -1

Fourth term = a2 =

an=an−1+9, where a1=−5

The formula = an = a1(n - 1) + d

a4 = -5(4 - 1)9

= -5(3) +9

= -15 +9

= -6

the answer is 62.8 cubic units