Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of -36.14 degrees Celsius and a boiling point of 324.84 degrees Celsius . What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state?

i. When the temperature is above F, it changes to gas.

ii. When the temperature is below F, it changes to solid.

Step-by-step explanation:

Matter generally exists in either a solid, liquid or gaseous form. With each phase having a certain range of temperature.

Temperature scale of a given substance can be either in Celsius, Fahrenheit or Kelvin. And conversion from one scale to another can be achieved. Example, Celsius scale can be converted to Fahrenheit by:

F = θ + 32

where: F is the equivalent temperature in Fahrenheit, θ is the value of temperature in degree Celsius.

Given that: melting point of the substance = C

⇒ F =   x + 32

      = F

The boiling point = C

F =   x   + 32

  = F

The melting point of the substance is F, and boiling point is F.

Therefore, the range of temperatures for which the substance is not in a liquid state are:

i. When the temperature is above F, it changes to gas.

ii. When the temperature is below F, it changes to solid.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°