The roots of x² - 4x = 5, in ascending order, are what?? PLEASE HELP

We want to find the roots of a quadratic equation, to do that, we will use the Bhaskara's formula.

For an equation like a*x^2 + b*x + c = 0

The solutions are given by:

Using that formula we will get that the solutions in ascending order are -1 and 5.

Now let's see how to get that:

We have expression: x^2 - 4x = 5

We can rewrite this as:

x^2 - 4x - 5 = 0

Now we can use the Bhaskara's formula to get:

Then the two solutions are:

x = (4 + 6)/2 = 5

x = (4 - 6)/2 = -1

Then the solutions in ascending order are -1 and 5.

If you want to learn more, you can read:

link

Step-by-step explanation:

x^2 - 4x - 5 = 0

(x - 5)(x + 1) = 0

x - 5 = 0

x = 5

x + 1 = 0

x = -1

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)