Suppose that two balanced dice are tossed repeatedly and the sum of the two uppermost faces is determined on each toss. a) What is the probability that we obtain a sum of 3 before we obtain a sum of 7? Hint: Let A denote the event of a sum of 3. Let B denote the event of no sum of 3 or 7. Now, begin to list the out the sample space in terms of A and B - it should be recognizable in the lecture notes. Hint: A useful infinite series result when |z| < 1: 1 + z + z 2 + z 3 + z 4 + . . . = 1 1 − z

this doesn't make sense lol

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step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.