70 POINTS. NEED HELP PLEASE! Write your own quadratic equation in standard form. Convert this quadratic to factored form. Be sure to show all of your work. Post to the discussion board these two equations and the work you did to convert from quadratic form to standard form.
Now write a new, different quadratic function, f of x, in standard form. Convert this quadratic function to factored form. Post to the discussion board both of these functions and the work you completed to convert from the quadratic form of the function to the factored form of the function.
Use your factored equation and your factored function to explain the differences between roots, x-intercepts, zeros, and solutions.

Standard equation:

1. ax^2+bx+c=0.

Quadratic formula:

2. x = -b+-sqrt(b^2-4ac)/2a. .

Now two equations to find the factored form through these formulas above.

Through this identifying a,b and c.

ax^2+bx+c=0.

x^2+4x-21=0

Here a=1, b=4, and c= -21

Now applying in the quadratic formula.

x=-4+-sqrt(4^2-4(1)(-21))/2(1)

Now solve it and it becomes

x=3 or x= -7.

Another example :

x^2+3x-4=0

Here a=1, b=3 and c=-4.

X=-3+-sqrt(3^2-4(1)(-4))/2(1)

Now solve it and

x= -4 and x=1

Step-by-step explanation: I got this from the person above they super smart ngl

The answer is belowa lot of words

Step-by-step explanation:

Standard equation:

1. ax^2+bx+c=0.

Quadratic formula:

2. x = -b+-sqrt(b^2-4ac)/2a. .

Now two equations to find the factored form through these formulas above.

Through this identifying a,b and c.

ax^2+bx+c=0.

x^2+4x-21=0

Here a=1, b=4, and c= -21

Now applying in the quadratic formula.

x=-4+-sqrt(4^2-4(1)(-21))/2(1)

Now solve it and it becomes

x=3 or x= -7.

Another example :

x^2+3x-4=0

Here a=1, b=3 and c=-4.

X=-3+-sqrt(3^2-4(1)(-4))/2(1)

Now solve it and

x= -4 and x=1

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

need more info

step-by-step explanation: