The graph of y= ax^2 + c contains the point (2,14). Which point lies on the graph of y=a(x-2)^2 + c?

(4, 14)

Step-by-step explanation:

We are given;

Graph of: y = ax² + c

That it contains point (2, 14)

Now,we want to find which point lies on the graph: y = a(x - 2)² + c.

Now, symbol "a" means the value of horizontal shift because the constants are grouped with x.

If the value of "a" is greater than 0,then it means that the graph shifted to the left by "a" units while if the value of "a" is less than 0,it means the graph shifted to the right by "a" units.

Now, from the 2 graph equations given, and from the principle of graph shifts, we can say that the first graph has shift by 2 units to the right because "a" equals -2.

What this implies is that every point on the graph y = ax² + c shifts by 2 units right.

Thus, the points that lie on the graph y = a(x - 2)² + c are: (x + 2, y)

Thus, points are: (2 + 2, 14) = (4, 14)

6mm^3 or .6cm^3

      216

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  36     6

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6     6   6

factor trees are nice.