Write an equation in slope-intercept form for the line that passes through (0, 1) and is perpendicular to the line whose equation is y = 2x? Ay= -2x + 1 B y = 2x + 1 C y = x + 1 Dy=-%2x + 1

y= -1/2 x + 1

Step-by-step explanation:

The line passes through point (0, 1) and is perpendicular to line with equation :

y=2x

Perpendicular lines are those that give -1 when the product of their slopes is calculated.

This means m₁ *m₂= -1

In this case, m₁=2, finding m₂ as;

m₁ * m₂ = -1

2  * m₂ = -1

      m₂ = -1/2

Using point  (0, 1),m₂ = -1/2, and imaginary line (x, y) then the equation of the line in slope-intercept form y= mx + b will be;

-1/2 = y-1/x-0

-1/2 x = y-1

1-1/2x = y

The equation will be ;

y= -1/2 x + 1

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

the answer is true.

step-by-step explanation: