Pls, help me solve this. Show your work

y = 2x + 1/3

Step-by-step explanation:

Since the line is parallel to y = 2x - 5, its slope is also 2x, as parallel lines have the same slope, leaving you with y = 2x.

Since it intercepts the y-axis at 1/3, and y = 2x intercepts the y-axis at 0, you will now need to add a 1/3 to the end of the equation for it to intersect the y-axis at the right place.

Therefore, the equation is: y = 2x + 1/3

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

25% is the answer