PLEASE HELP!! If f (x) = x^3 - x^2 + x - 1, then f’(2) =

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Work Shown:

f(x) = x^3 - x^2 + x - 1

f ' (x) = 3x^2 - 2x + 1

f ' (2) = 3(2)^2 - 2(2) + 1

f ' (2) = 9

In step 2, I used the power rule

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

mnkjn

step-by-step explanation: