The sum of 3 consecutive odd integers is 36. Whal
consecutive odd integers

Any odd number can be represented with 2n+1 where n is a whole number. Also, since the next consecutive number will be even (2n+1+1), then the next consecutive odd number must be 2n+1+2, or 2n+3. Since consecutive odd numbers are separated by 2, then the previous odd number should be 2n-1. So:

Now in order to find three odd consecutive numbers that will sum to 36, you must be able to divide 11 evenly by 2, and have a whole number as a result. This is impossible, so there aren't any 3 odd numbers that will sum to 36.

i have no clue at all sorry

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.