Maya has a smart phone data plan that costs $50 per month that includes 2 GB of dat, but will charge extra $15 per GB over the included amount. How much would Maya have to pay in a month where she used 3 GB over a limit? How much would maya have to pay in a month where she used over by x GB?

a. $65

b. $(50 + 15x)

Step-by-step explanation:

A. From the question, we are told that the first 2 GB of data costs $50 while the subsequent extra GB cost $15 per GB

so for 3 GB, the normal $50 is charged for the first 2 GB while an extra $15 is charged for the extra 1 GB

so, the total amount charged for 3 GB will be $50 + $15 = $65

B. Amount to be paid in a month where x GB is used over the normal

Firstly, she will pay the $50 , then for the extra she will be paying $15 * x = $15x

So the amount to be paid will be;

$50 + $15x = $(50 + 15x)

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.