Darpana solved the equation s = StartFraction a + b + c Over 3 EndFraction for a. Her steps are shown below: 1. Multiply by 3: s = StartFraction a + b + c Over 3 EndFraction. 3 s = a + b + c. 2. Subtract b: 3 s minus b = a + b + c minus b. 3 s minus b = a + c. 3. Divide by c: StartFraction 3 s minus b Over c EndFraction = a. Which statement about Darpana's work is true? In step 1 she needed to divide by 3 rather than multiply. In step 2 she needed to add b rather than subtract. In step 3 she needed to subtract c rather than divide. Darpana solved the equation correctly.

Option (c) is correct.

Step-by-step explanation:

Given equation is :

The equation can be solved for a as follows :

Step 1.

Cross multiply the given equation

Step 2.

Now subtract b on both sides

3s-b = a+b+c-b

3s-b = a+c

Step 3.

Subtract c on both sides

3s-b-c=a+c-c

⇒ a=3s-b-c

The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;