What is the equation of the line that passes through (6,4) and (4,1)

y = 3/2*x - 5

Step-by-step explanation:

Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:

P1=(x1,y1) and P2=(x2,y2)

slope formula --->   m=(y2-y1)/(x2-x1)

Replacing the given points --->    m=(1-4)/(4-6) = 3/2

then replacing the slope value obtained:

y = 3/2*x + b

Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:

1 = 3/2*4 + b

1 = 6 + b

1 - 6 = b

-5 = b

therefore the line equation is:

y = 3/2*x - 5