what is the slope of the line that passes through the points (7,-6) and (4,-6)? write your answer in simplest form

m = 0, y = -6

Step-by-step explanation:

using point slope form :

y-y1=m(x-x1) ; initial point (x1,y1) = (4,-6), final point (x,y) = (7,-6).

one substituted, it should look like this:

-6--6 = m(7-4),

-6+6= m(7-4)

0 = m(7-4)

0 = 3m

0/3 = 3/3m

0 = m

m = 0/3 = 0

for the points

step-by-step explanation:

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!