What is the remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2? A. -23
B. 23
C. -3
D. 3

The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

A polynomial is an expression consisting of the operations of addition, subtraction, multiplication of variables.

Polynomial based on degree is linear, quadratic, cubic.

The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial x - a, the remainder of is to f(a)

Given that f(x) = 2x⁴ + x³ - 8x - 1 is divided by x - 2

x - 2 = 0

x = 2

f(2) = 2(2)⁴ + (2)³ - 8(2) - 1 = 23

Hence The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

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By the remainder theorem, dividing by leaves a remainder of , which is

which makes B the correct answer.

step-by-step explanation:

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.