The distribution of speeds along a certain stretch of highway has an mean of 76 mph and a standard deviation of 7 mph.
What percentage of cars would be traveling slower than 55 mph?

0.13%

Step-by-step explanation:

Given that :

Mean = 76mph

Standard deviation = 7 mph

Percentage of cars traveling slower than 55mph

Obtain the Zscore :

X = 55mph

Zscore = (X - mean) / standard deviation

Zscore = (55 - 76) / 7

Zscore = - 3

P(Z < - 3)

From the z table :

P(Z < - 3) = 0.0013

Hence, percentage of cars traveling slower than 55mph is (0.0013 * 100%) = 0.13%

could

step-by-step explanation:

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