Logan and Nathan are shelving books at a public library. Logan shelves 5 books at a time, whereas Nathan shelves 6 books at a time. If they end up shelving the same number of books, what is the smallest number of books each could have shelved?

30

Step-by-step explanation:

Given that

Logan shelves 5 books and

Nathan shelves 6 books

They end shelving the same number of books.

To find:

Smallest number of books each could have shelved?

Solution:

First of all, let us have a look at the definition of Least Common Multiple(LCM) of two numbers.

Least Common Multiple (LCM) of two numbers is the minimum number which is divisible by both the numbers.

Now, looking at the statement of the given question.

We have to find the LCM of both the numbers actually.

Making factors of the numbers:

Nothing is common here, therefore the LCM is .

Smallest number of books shelved = 30

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk