Linear equation A line with the slope of 1/2 pass through the point (3,-2)
a) Write the equation of the line in Point - Slope Form.
b) Write the equation of the line in Slope - intercept form.

see explanation

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = and (a, b) = (3, - 2) , thus

y - (- 2) = (x - 3) , that is

y + 2 = ( x - 3) ← in point- slope form

(b)

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = , thus

y = x + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = + c ⇒ c = - 2 - = -

y = x - ← in slope- intercept form

b. 2

step-by-step explanation:

the slope of a line =δy/δx

δy= y₂-y₁

δx= x₂-x₁

therefore, using the points (-2,-3)   and (3,7) we can calculate gradient as follows:

m=(7--3)/(3--2) (a number minus a negative number the sign changes to a plus)

m=(7+10)/(3+2)

=10/5

=2

answer: 1 and 3

step-by-step explanation: