Some information about the surface area and volume of two similar solids has been given fill in the missing value.

1216 yd³

Step-by-step explanation:

GivenSolid 1                                   |     Solid 2Surface area = 1100 yd²       |     Surface area = 176 yd²Volume = 19000 yd³            |     Volume = xSolids are similar

Let the scale factor be k, then

Surface area is a product of 2 dimensions so the ratio of surface area of the solids would be k²Volume is the product of 3 dimensions so the ratio of volumes would be k³

Considering this we have:

1100 = 176*k²19000 = x*k³

The value of x is

x = 19000/k³

Finding the scale factor

k= √1100/176 = 2.5

So the answer is

x = 19000/2.5³ = 1216 yd³

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