PLSS HELP A trapezoid has a base of 4.5 inches, a height of 6 inches, and an area of 21 square inches. The equation below can be used to determine b2, the length in inches of the second base of the trapezoid.

12(4.5+b2)(6)=21

What is the length, in inches, of the second base of the trapezoid?

The second base of the trapezoid b2 is 2.5 inches

Step-by-step explanation:

Here, we want to calculate the second base of the trapezoid.

Mathematically, the area of a trapezoid can be given as;

A = 1/2(a + b) h

where a and b represents the parallel bases and h is the height of the trapezoid

so this, we have from the question

1/2(4.5 + b2) * 6 = 21

3(4.5 + b2) = 21

divide both sides by 3

4.5 + b2 = 7

b2 = 7-4.5

b2 = 2.5 inches

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

what do u need to know

step-by-step explanation: