The width of a classroom is 4 meters less than the length, and the area is 192 m^2. If the length is x m, find an equation in x and hence, find the dimensions of the classroom.

length-x

width-x-4

area-- length* width

192=X*(X-4)

x^2-4x-192=0

x^2-16x+12x-192=0

X(x-16)+12(x-16)=0

(x-16),(X+12)

X= 16 because X cannot be negative like (-12)

the dimensions of the classroom will be

length = 16

width = 12

I hope this will help everyone

the correct answer would be the third option

a and c

for infinitely many solutions we require both left and right sides to be equal

distribute and simplify

a

14 - 8x = 20 - 8x - 6 = 14 - 8x ← both sides equal so infinite solutions

b

6x - 54 = 6x - 54 + x = 7x - 54 ← not equal

c

4x + 16 = 4x + 10 + 6 = 4x + 16 ← both sides equal so infinite solutions

d

5x - 40 + 10 = 5x + 10

5x - 30 = 5x + 10 ← not equal