Calculate the mean ,median, or mode of a distribution. There are 10 bags containing tickets numbered 1 to 20. Ten students draw a ticket from each bag. One student drew tickets with the numbers. 5,8,18,1,14,6,8,13,8,19 what would be the correct mean, median, and mode

Step-by-step explanation:

Mean = sum of variables/sample size

Sum of variables = 5+8+18+1+14+6+8+13+8+19

Sum of variables = 100

Sample size = 10

Mean = 100/10

Mean = 10

Median is the value at the centre after rearrangement.

On rearrangement

1,5,6,8),8,8,(13,14,18,19

Median = 8+8/2

Median = 16/2

Median = 8

Mode is the value with the highest frequency. The value that occur the most. From the datas, the mode is 8 since it occurred 3 times.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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