physics convention 11 companies set up equal sized square booths in a row along one wall of a convention center. The booths are adjacent to each other and a 2-ft wide walkway surrounds the block of booths on three sides. The total area of the booths and walkway is 1200 ft^2. What is the side length of each booth?

Side length of each booth is 8.35 ft approximately.

Step-by-step explanation:

There are 11 companies set up equal sized square booths in a row along one wall of a convention center.

Now, refer the diagram to answer the problem.

It is given area is 1200.

So, length x width =1200

(11x+24)(x+2)=1200

Multiply using FOIL method.

+22x+24x+48=1200

+46x+48-1200=0

+46x-1152=0

Solve using quadratic formula

x=

x=

x=

Simplify it

Simplify to get two values for x.

x=8.35; x=-12.67

Here negative does not work.

Side length of each booth is 8.35 ft.

took the test it's 94

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.