Frank and Jasmine use the same trail for their Saturday walk. Frank walks at an average pace of 2 miles per hour. Jasmine starts when Frank is at the 3 mile marker and walks at an average pace of 4 miles per hour. Write an algebraic equation that could be used to determine how many hours Jasmine will walk before she catches up to Frank.

Step-by-step explanation:

let the distance of the trail be x

and let the time be t

given that franks average speed is 2 miles per hour

the distance covered by Frank is x-3

the time taken by Frank to cover the distance is

we know that speed=distance/time

2=x-3/t

2t=x-3  

x=2t+31

Jasmine speed= 4 miles per hour

speed=distance/time

4=x/t

x=4t2

equating 1 and 2 above we have

2t+3=4t

solving for t we have

4t-2t=3

2t=3

t=3/2

t=1.5

That is 1hr 30 min

4 + 5 7/9= 9 7/9

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)