Show so that the expression of cos4A in term of SinA is 8Sin^4 - 8Sin^2A + 1 plz solve anyone.. I really need this answer

Step-by-step explanation:

L

H

S

=

cos

4

x

=

2

cos

2

(

2

x

)

−

1

=

2

(

cos

(

2

x

)

)

2

−

1

=

2

(

2

cos

2

x

−

1

)

2

−

1

=

2

(

4

cos

4

x

−

4

cos

2

x

+

1

)

−

1

=

8

cos

4

x

−

8

cos

2

x

+

2

−

1

=

8

cos

4

x

−

8

cos

2

x

+

1

=

R

H

S

Again

L

H

S

=

cos

4

x

=

2

cos

2

(

2

x

)

−

1

=

2

(

1

−

2

sin

2

x

)

)

2

−

1

=

2

(

1

−

4

sin

2

x

+

4

sin

4

x

)

−

1

=

2

−

8

sin

2

x

+

8

sin

4

x

−

1

=

8

sin

4

x

−

8

sin

2

x

+

1

=

R

H

S

sin

2

x

+

cos

2

x

=

1

cos

2

x

=

1

−

sin

2

x

substitute in the equation as follows

8

cos

4

x

−

8

cos

2

x

+

1

=

8

cos

2

x

(

cos

2

x

−

1

)

+

1

=

8

(

1

−

sin

2

x

)

(

1

−

sin

2

x

−

1

)

+

1

=

8

(

1

−

sin

2

x

)

(

−

sin

2

x

)

+

1

=

8

sin

4

x

−

8

sin

2

x

+

1

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.