What is the equation of the line that is perpendicular to y equals negative four x plus five and passes through the point four comma negative three ?

y= 1/4x - 4

Step-by-step explanation:

use point slope form which is:

y - y1 = m(x - x1)

we know that the slope will be 1/4 because perpendicular is a negative reciprocal.

plug everything into point slope form:

y + 3 = 1/4 ( x - 4)

we distribute the 1/4 and then subtract the three and we get our answer

y= 1/4x - 4

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )