Simultaneous Equations 2x+3y=3750, 4x+y=4250

The answer is x=900 and y=650
I just need the steps

It's long but you use Substitution!

Step-by-step explanation:

Let's solve your system by substitution.

2x+3y=3750;4x+y=4250

Rewrite equations:

4x+y=4250;2x+3y=3750

Step: Solve 4x+y=4250 for y:

4x+y = 4250

4x+y+−4x = 4250+−4x (Add -4x to both sides)

y = −4x+4250

Step: Substitute −4x+4250 for y in 2x+3y = 3750:

2x+3y=3750

2x+3(−4x+4250)=3750

−10x+12750=3750 (Simplify both sides of the equation)

−10x+12750+−12750=3750+−12750 (Add -12750 to both sides)

−10x =−9000

−10x = −9000 (Divide both sides by -10)

−10          −10

x=900

Step: Substitute 900 for x in y = −4x+4250:

y=−4x+4250

y=(−4)(900)+4250

y=650 (Simplify both sides of the equation)

x=900 and y=650

109 is the nearest whole number/final answer! : )