The formula determines the magnitude of an earthquake, where I is the intensity of the earthquake and S is the intensity of a “standard earthquake.” How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6? Show your work.

An earthquake with a magnitude of 8 is 100 times stronger than an earthquake with a magnitude of 6.

Given the following data:

To determine how many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6:

Mathematically, the magnitude of an earthquake is given by the formula:

Where:

For earthquake A:

For earthquake B:

For strength:

Strength = 100

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100

Step-by-step explanation:

M = log(I/S)

The intensity of the first earthquake:

8 = log(I₁/S)

10⁸ = I₁/S

I₁ = 10⁸ S

The intensity of the second earthquake:

6 = log(I₂/S)

10⁶ = I₂/S

I₂ = 10⁶ S

The ratio is:

I₁/I₂ = (10⁸ S) / (10⁶ S)

I₁/I₂ = 100

It is 100 times stronger.

answer: this is not a question

step-by-step explanation: this is a answer

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9