Find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than the largest number.

Step-by-step explanation:

Consecutive even integers increase by 2.

x   ← an integer

2x  ← an even integer (the smallest)

2x+2   ← next even integer consecutive to 2x (the middle one)

2x+2+2=2x+4  ← the last even integer consecutive to 2x+2 (the largest)

2(2x+2)    ← twice the middle number

2x+2(2x+2)   ←  the sum of the smallest number and twice the middle

2x+4+20   ←  20 more than the largest number

2x + 2(2x + 2) = 2x + 4 + 20

2x + 4x + 4 = 2x + 24

            -4           -4

            6x = 2x + 20

         -2x       -2x

            4x = 20

            ÷2     ÷2

            2x = 10

2x+2 = 10+2 = 12

2x+4 = 10+4 = 14

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)