The equation (k + 3) x^2+ 6x + k = 5, where k is a constant,
has two distinct real solutions for x.
Show that k satisfies
k^2– 2k – 24 < 0

Get an answer for 'The equation(k+3)x^2+6x+k = 5, where k is a constant, has two distinct real solutions for x.Show that k satisfies k^2-2k-24<0' and find ...Step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

i believe the answer is letter c) 8

step-by-step explanation: