Find the 14th term of the geometric sequence 5 -10 20

  a14 = -40,960

Step-by-step explanation:

The sequence has a first term of 5 and a common ratio of -10/5 = -2, so the n-th term is given by ...

  an = a1·r^(n-1)

  an = 5·(-2)^(n-1)

The 14th term is then ...

  a14 = 5·(-2)^(14-1) = -5·2^13 = -5·8192

  a14 = -40,960

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral