A steel ball whose mass is 2.0 kg is rolling at a rate of 2.8 m/s. What is its momentum? 1) 1.4 kgm/s

2) .71 kgm/s

3) 5.6 kgm/s

4) 4.8 kgm/s

mxv

Step-by-step explanation:

2.0x2.8=5.6

momentums equation is mass times velocity so 2.0kg is the mass and you multiply it by the velocity which is 2.8m/s and that is how you get your answer. your answer is number 3

step-by-step explanation:

your mom

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: