Solve these simultaneous equations
3p + 7q = 56
5p + 7q = 70

P= and q=

P = 7 and q = 5

Step-by-step explanation:

Step-by-step explanation:

3p + 7q= 56...(1 )

5p + 7q = 70 (2)

Using elimination method to solve this

Substract equation 1 from 2 , this becomes:

5p - 3p + 7q-7q = 70-56

5p-3p + 0 = 15

2p = 14

Next step is to divide both 2 to get p

2p/2 = 14/2

P= 7

To get q, input p= 7 into equation 1 which is

3p +7q =56, 3(7) + 7q= 56

21+ 7q = 56, 7q= 56-21

7q= 35( divide both sides by 7)

q = 5.

Since p= 7 and q= 5, let's input values for p and q into both equation.

Equation 1: 3p + 7q= 56

3(7) + 7(5) = 56,

21 + 35 = 56.

For equation 2: 5p + 7q = 70

5(7) + 7(5) = 35 + 35 = 70.

answer is c

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )