Match each polynomial with its factorization. 1. y 2 - y - 2 (y - 6)2 2. 3y 2 - 27 (y - 2)(y + 2)(y2 + 4) 3. y 4 - 16 (4y - 3)(y + 2) 4. y 2 - 12y + 36 3(y - 3)(y + 3) 5. -4y 2 + 8y + 32 -4(y + 2)( y - 4) 6. 5y - 2 + 4y 2 - 4 (y + 1)(y - 2)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

need more information

step-by-step explanation: